首页
编程语言
数据库
网络开发
Algorithm算法
移动开发
系统相关
金融统计
人工智能
其他
首页
>
> 详细
辅导COMP9021、Python程序语言调试、辅导Python、讲解tangram留学生 调试C/C++编程|调试Web开发
Assignment 2
COMP9021, Trimester 1, 2019
1. General matter
1.1. Aims. The purpose of the assignment is to:
design and implement an interface based on the desired behaviour of an application program;
practice the use of Python syntax;
develop problem solving skills.
1.2. Submission. Your program will be stored in a file named tangram.py. After you have developed and
tested your program, upload it using Ed (unless you worked directly in Ed). Assignments can be submitted
more than once; the last version is marked. Your assignment is due by April 28, 11:59pm.
1.3. Assessment. The assignment is worth 10 marks. It is going to be tested against a number of input files.
For each test, the automarking script will let your program run for 30 seconds.
Late assignments will be penalised: the mark for a late submission will be the minimum of the awarded mark
and 10 minus the number of full and partial days that have elapsed from the due date.
1.4. Reminder on plagiarism policy. You are permitted, indeed encouraged, to discuss ways to solve the
assignment with other people. Such discussions must be in terms of algorithms, not code. But you must
implement the solution on your own. Submissions are routinely scanned for similarities that occur when students
copy and modify other people’s work, or work very closely together on a single implementation. Severe penalties
apply.
12
2. Background
The game of tangram consists in creating shapes out of pieces. We assume that each piece has its own colour,
different to the colour of any other piece in the set we are working with. Just for reference, here is the list of
colours that are available to us (you will not make use of this list):
https://www.w3.org/TR/2011/REC-SVG11-20110816/types.html#ColorKeywords
A representation of the pieces will be stored in an .xml file thanks to a simple, fixed syntax.
2.1. Pieces. Here is an example of the contents of the file pieces_A.xml, typical of the contents of any file of
this kind (so only the number of pieces, the colour names, and the various coordinates can differ from one such
file to another–we do not bother with allowing for variations, in the use of space in particular).
Opened in a browser, pieces_A.xml displays as follows:
Note that the coordinates are nonnegative integers. This means that the sets of pieces we consider rule out
those of the traditional game of tangram, where √
2 is involved everywhere...
We require every piece to be a convex polygon. An .xml file should represent a piece with n sides (n ≥ 3)
by an enumeration of n pairs of coordinates, those of consecutive vertices, the first vertex being arbitrary, and
the enumeration being either clockwise or anticlockwise.
The pieces can have a different orientation and be flipped over. For instance, the file pieces_AA.xml whose
contents is
3
and which displays as
represents the same set of pieces (the fact that the latter appear as smaller than the former is just due to the
different scaling of the included pdf’s; the sizes of the pieces are actually the same in terms of the coordinates
of their vertices).
The pieces can overlap, but that does not concern us. In practice, we will just use representations where the
pieces do not overlap as that allows us to visualise the pieces properly when we open the corresponding .xml
file, but it is just for convenience and irrelevant to the tasks we tackle.
2.2. Shapes. A representation of a shape is provided thanks to an .xml file with the same structure, storing
the coordinates of the vertices of just one polygon.
The file shape_A_1.xml whose contents is
and which displays as
is such an example. The file shape_A_2.xml whose contents is
and which displays as4
is another such example.
Contrary to pieces, shapes are not assumed to be convex polygons. Still they are assumed to be simple
polygons (the boundary of a simple polygon does not cross itself; in particular, it cannot consist of at least 2
polygons that are connected by letting two of them just “touch” each other at one of their vertices–e.g., two
rectangles such that the upper right corner of one rectangle is the lower left corner of the other rectangle; that
is not allowed).
Whereas you will have to check that the representation of the pieces in an .xml file satisfies our constraints,
you will not have to do so for the representation of a shape; you can assume that any shape we will be dealing
with satisfies our constraints.
2.3. Tangrams. The first shape can be built from our set of pieces, in many ways. Here is one, given by the
file tangram_A_1_a.xml whose contents is
and which displays as follows.
Here is another one, given by the file tangram_A_1_b.xml whose contents is
5
and which displays as follows.
The second shape can also be built from our set of pieces, in many ways. Here is one, given by the file
tangram_A_2_a.xml whose contents is
and which displays as follows.
Here is another one, given by the file tangram_A_2_b.xml whose contents is
and which displays as follows.67
3. First task (3 marks)
You have to check that the pieces represented in an .xml file satisfy our constraints. So you have to check
that each piece is convex, and if it represents a polygon with n sides (n ≥ 3) then the representation consists
of an enumeration of the n vertices, either clockwise or anticlockwise. Here is the expected behaviour of your
program.
$ python3
...
>>> from tangram import *
>>> file = open('pieces_A.xml')
>>> coloured_pieces = available_coloured_pieces(file)
>>> are_valid(coloured_pieces)
True
>>> file = open('pieces_AA.xml')
>>> coloured_pieces = available_coloured_pieces(file)
>>> are_valid(coloured_pieces)
True
>>> file = open('incorrect_pieces_1.xml')
>>> coloured_pieces = available_coloured_pieces(file)
>>> are_valid(coloured_pieces)
False
>>> file = open('incorrect_pieces_2.xml')
>>> coloured_pieces = available_coloured_pieces(file)
>>> are_valid(coloured_pieces)
False
>>> file = open('incorrect_pieces_3.xml')
>>> coloured_pieces = available_coloured_pieces(file)
>>> are_valid(coloured_pieces)
False
>>> file = open('incorrect_pieces_4.xml')
>>> coloured_pieces = available_coloured_pieces(file)
>>> are_valid(coloured_pieces)
False
Note that the function are_valid() does not print out True or False, but returns True or False.8
4. Second task (3 marks)
You have to check whether the sets of pieces represented in two .xml files are identical, allowing for pieces
to be flipped over and allowing for different orientations. Here is the expected behaviour of your program.
$ python3
...
>>> from tangram import *
>>> file = open('pieces_A.xml')
>>> coloured_pieces_1 = available_coloured_pieces(file)
>>> file = open('pieces_AA.xml')
>>> coloured_pieces_2 = available_coloured_pieces(file)
>>> are_identical_sets_of_coloured_pieces(coloured_pieces_1, coloured_pieces_2)
True
>>> file = open('shape_A_1.xml')
>>> coloured_pieces_2 = available_coloured_pieces(file)
>>> are_identical_sets_of_coloured_pieces(coloured_pieces_1, coloured_pieces_2)
False
Note that the function identical_sets_of_coloured_pieces() does not print out True or False, but
returns True or False.9
5. Third task (4 marks)
You have to check whether the pieces represented in an .xml file are a solution to a tangram puzzle represented
in another .xml file. Here is the expected behaviour of your program.
$ python3
...
>>> from tangram import *
>>> file = open('shape_A_1.xml')
>>> shape = available_coloured_pieces(file)
>>> file = open('tangram_A_1_a.xml')
>>> tangram = available_coloured_pieces(file)
>>> is_solution(tangram, shape)
True
>>> file = open('tangram_A_2_a.xml')
>>> tangram = available_coloured_pieces(file)
>>> is_solution(tangram, shape)
False
Note that the function is_solution() does not print out True or False, but returns True or False.
联系我们
QQ:99515681
邮箱:99515681@qq.com
工作时间:8:00-21:00
微信:codinghelp
热点文章
更多
辅导 comm2000 creating socia...
2026-01-08
讲解 isen1000 – introductio...
2026-01-08
讲解 cme213 radix sort讲解 c...
2026-01-08
辅导 csc370 database讲解 迭代
2026-01-08
讲解 ca2401 a list of colleg...
2026-01-08
讲解 nfe2140 midi scale play...
2026-01-08
讲解 ca2401 the universal li...
2026-01-08
辅导 engg7302 advanced compu...
2026-01-08
辅导 comp331/557 – class te...
2026-01-08
讲解 soft2412 comp9412 exam辅...
2026-01-08
讲解 scenario # 1 honesty讲解...
2026-01-08
讲解 002499 accounting infor...
2026-01-08
讲解 comp9313 2021t3 project...
2026-01-08
讲解 stat1201 analysis of sc...
2026-01-08
辅导 stat5611: statistical m...
2026-01-08
辅导 mth2010-mth2015 - multi...
2026-01-08
辅导 eeet2387 switched mode ...
2026-01-08
讲解 an online payment servi...
2026-01-08
讲解 textfilter辅导 r语言
2026-01-08
讲解 rutgers ece 434 linux o...
2026-01-08
热点标签
mktg2509
csci 2600
38170
lng302
csse3010
phas3226
77938
arch1162
engn4536/engn6536
acx5903
comp151101
phl245
cse12
comp9312
stat3016/6016
phas0038
comp2140
6qqmb312
xjco3011
rest0005
ematm0051
5qqmn219
lubs5062m
eee8155
cege0100
eap033
artd1109
mat246
etc3430
ecmm462
mis102
inft6800
ddes9903
comp6521
comp9517
comp3331/9331
comp4337
comp6008
comp9414
bu.231.790.81
man00150m
csb352h
math1041
eengm4100
isys1002
08
6057cem
mktg3504
mthm036
mtrx1701
mth3241
eeee3086
cmp-7038b
cmp-7000a
ints4010
econ2151
infs5710
fins5516
fin3309
fins5510
gsoe9340
math2007
math2036
soee5010
mark3088
infs3605
elec9714
comp2271
ma214
comp2211
infs3604
600426
sit254
acct3091
bbt405
msin0116
com107/com113
mark5826
sit120
comp9021
eco2101
eeen40700
cs253
ece3114
ecmm447
chns3000
math377
itd102
comp9444
comp(2041|9044)
econ0060
econ7230
mgt001371
ecs-323
cs6250
mgdi60012
mdia2012
comm221001
comm5000
ma1008
engl642
econ241
com333
math367
mis201
nbs-7041x
meek16104
econ2003
comm1190
mbas902
comp-1027
dpst1091
comp7315
eppd1033
m06
ee3025
msci231
bb113/bbs1063
fc709
comp3425
comp9417
econ42915
cb9101
math1102e
chme0017
fc307
mkt60104
5522usst
litr1-uc6201.200
ee1102
cosc2803
math39512
omp9727
int2067/int5051
bsb151
mgt253
fc021
babs2202
mis2002s
phya21
18-213
cege0012
mdia1002
math38032
mech5125
07
cisc102
mgx3110
cs240
11175
fin3020s
eco3420
ictten622
comp9727
cpt111
de114102d
mgm320h5s
bafi1019
math21112
efim20036
mn-3503
fins5568
110.807
bcpm000028
info6030
bma0092
bcpm0054
math20212
ce335
cs365
cenv6141
ftec5580
math2010
ec3450
comm1170
ecmt1010
csci-ua.0480-003
econ12-200
ib3960
ectb60h3f
cs247—assignment
tk3163
ics3u
ib3j80
comp20008
comp9334
eppd1063
acct2343
cct109
isys1055/3412
math350-real
math2014
eec180
stat141b
econ2101
msinm014/msing014/msing014b
fit2004
comp643
bu1002
cm2030
联系我们
- QQ: 99515681 微信:codinghelp
© 2024
www.7daixie.com
站长地图
程序辅导网!